What are the solutions to the equation 4p^2-12p+9=0 ?

The solutions to the equation 4p^2-12p+9=0 are p= 3/2

Find the zeros of 4p^2-12p+9=0

The zeros of 4p^2-12p+9=0 are p= 3/2

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4 p^{2} - 12 p + 9 = 0

p = \frac{3}{2}

Decimal Notation

p = 1.5

Solution steps

4 p^{2} - 12 p + 9 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

p_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

p = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

p = \frac{3}{2}

The solution to the quadratic equation is:

p = \frac{3}{2}

9 (- 4 + 2 v) + 7 v = - 211

(x + 2) (x - 1) (x - 3) > 0

180 - 16 x^{2} = 0

\frac{x}{2} + 7 \geq 2

c^{3} - 27

What are the solutions to the equation 4p^2-12p+9=0 ?
The solutions to the equation 4p^2-12p+9=0 are p= 3/2
Find the zeros of 4p^2-12p+9=0
The zeros of 4p^2-12p+9=0 are p= 3/2