What are the solutions to the equation x^2=16-4x ?

The solutions to the equation x^2=16-4x are x=2(sqrt(5)-1),x=-2(1+sqrt(5))

Find the zeros of x^2=16-4x

The zeros of x^2=16-4x are x=2(sqrt(5)-1),x=-2(1+sqrt(5))

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x^{2} = 16 - 4 x

x = 2 (5 - 1), x = - 2 (1 + 5)

Decimal Notation

x = 2.47213 \dots, x = - 6.47213 \dots

Solution steps

x^{2} = 16 - 4 x

Move

4 x

to the left side

x^{2} + 4 x = 16

Move

16

to the left side

x^{2} + 4 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 16) = 45

x_{1, 2} = \frac{- 4 \pm 4 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 5}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 5}{2 \cdot 1}

x = \frac{- 4 + 4 5}{2 \cdot 1} : 2 (5 - 1)

x = \frac{- 4 - 4 5}{2 \cdot 1} : - 2 (1 + 5)

The solutions to the quadratic equation are:

x = 2 (5 - 1), x = - 2 (1 + 5)

\frac{( 4 x ^{2} y ^{3} z ^{4} ) ^{2}}{2 z ^{3}}

5 x - 7 > 4 x + 8

∣ - 2 x + 17 ∣ \geq 10

10 + 3 y - 2 = 4 y - y + 8

\frac{4 ^{8}}{4 ^{3}}

What are the solutions to the equation x^2=16-4x ?
The solutions to the equation x^2=16-4x are x=2(sqrt(5)-1),x=-2(1+sqrt(5))
Find the zeros of x^2=16-4x
The zeros of x^2=16-4x are x=2(sqrt(5)-1),x=-2(1+sqrt(5))