What are the solutions to the equation 15p^2+80=-80p ?

The solutions to the equation 15p^2+80=-80p are p=-4/3 ,p=-4

Find the zeros of 15p^2+80=-80p

The zeros of 15p^2+80=-80p are p=-4/3 ,p=-4

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15 p^{2} + 80 = - 80 p

p = - \frac{4}{3}, p = - 4

Decimal Notation

p = - 1.33333 \dots, p = - 4

Solution steps

15 p^{2} + 80 = - 80 p

Move

80 p

to the left side

15 p^{2} + 80 + 80 p = 0

Write in the standard form

a x^{2} + b x + c = 0

15 p^{2} + 80 p + 80 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 15 \cdot 80}{2 \cdot 15}

8 0^{2} - 4 \cdot 15 \cdot 80 = 40

p_{1, 2} = \frac{- 80 \pm 40}{2 \cdot 15}

Separate the solutions

p_{1} = \frac{- 80 + 40}{2 \cdot 15}, p_{2} = \frac{- 80 - 40}{2 \cdot 15}

p = \frac{- 80 + 40}{2 \cdot 15} : - \frac{4}{3}

p = \frac{- 80 - 40}{2 \cdot 15} : - 4

The solutions to the quadratic equation are:

p = - \frac{4}{3}, p = - 4

36 m^{4} - 12 m^{3} - 8 m^{2}

- 4 + \frac{r}{2} = - 8

322

m^{2} + 71 mn - 14 m^{2} - 65 mn + m^{3} - m^{2} - 115 m^{2} + 6 m^{3}

x^{2} = 2 x + 24

What are the solutions to the equation 15p^2+80=-80p ?
The solutions to the equation 15p^2+80=-80p are p=-4/3 ,p=-4
Find the zeros of 15p^2+80=-80p
The zeros of 15p^2+80=-80p are p=-4/3 ,p=-4