What are the solutions to the equation 12t^2-3t+3=0 ?

The solutions to the equation 12t^2-3t+3=0 are t= 1/8+i(sqrt(15))/8 ,t= 1/8-i(sqrt(15))/8

Find the zeros of 12t^2-3t+3=0

The zeros of 12t^2-3t+3=0 are t= 1/8+i(sqrt(15))/8 ,t= 1/8-i(sqrt(15))/8

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12 t^{2} - 3 t + 3 = 0

t = \frac{1}{8} + i \frac{15}{8}, t = \frac{1}{8} - i \frac{15}{8}

Solution steps

12 t^{2} - 3 t + 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 12 \cdot 3}{2 \cdot 12}

Simplify

(- 3)^{2} - 4 \cdot 12 \cdot 3 : 315 i

t_{1, 2} = \frac{- ( - 3 ) \pm 3 15 i}{2 \cdot 12}

Separate the solutions

t_{1} = \frac{- ( - 3 ) + 3 15 i}{2 \cdot 12}, t_{2} = \frac{- ( - 3 ) - 3 15 i}{2 \cdot 12}

t = \frac{- ( - 3 ) + 3 15 i}{2 \cdot 12} : \frac{1}{8} + i \frac{15}{8}

t = \frac{- ( - 3 ) - 3 15 i}{2 \cdot 12} : \frac{1}{8} - i \frac{15}{8}

The solutions to the quadratic equation are:

t = \frac{1}{8} + i \frac{15}{8}, t = \frac{1}{8} - i \frac{15}{8}

4 x^{2} + 7 x - 15

x^{2} = 2 x - 17

2 x^{3} + 9 x^{2} + 4 x + 18

2 y^{2} - y - 1 = 0

- 3 x^{2} + 18 x - 4 = 0

What are the solutions to the equation 12t^2-3t+3=0 ?
The solutions to the equation 12t^2-3t+3=0 are t= 1/8+i(sqrt(15))/8 ,t= 1/8-i(sqrt(15))/8
Find the zeros of 12t^2-3t+3=0
The zeros of 12t^2-3t+3=0 are t= 1/8+i(sqrt(15))/8 ,t= 1/8-i(sqrt(15))/8