What are the solutions to the equation -3x^2+1=0 ?

The solutions to the equation -3x^2+1=0 are x= 1/(sqrt(3)),x=-1/(sqrt(3))

Find the zeros of -3x^2+1=0

The zeros of -3x^2+1=0 are x= 1/(sqrt(3)),x=-1/(sqrt(3))

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- 3 x^{2} + 1 = 0

x = \frac{1}{3}, x = - \frac{1}{3}

Decimal Notation

x = 0.57735 \dots, x = - 0.57735 \dots

Solution steps

- 3 x^{2} + 1 = 0

Move

1

to the right side

- 3 x^{2} = - 1

Divide both sides by

- 3

x^{2} = \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{3}, x = - \frac{1}{3}

\frac{1}{3} = \frac{1}{3}

- \frac{1}{3} = - \frac{1}{3}

x = \frac{1}{3}, x = - \frac{1}{3}

x^{2} - 16 > 0

8 y^{2} + 22 y + 9

5 < 3 x + 2 \leq 9

- \frac{1}{1}

y^{2} - 49 + 14 x - x^{2}

What are the solutions to the equation -3x^2+1=0 ?
The solutions to the equation -3x^2+1=0 are x= 1/(sqrt(3)),x=-1/(sqrt(3))
Find the zeros of -3x^2+1=0
The zeros of -3x^2+1=0 are x= 1/(sqrt(3)),x=-1/(sqrt(3))