What are the solutions to the equation 4x^2-2x-7=0 ?

The solutions to the equation 4x^2-2x-7=0 are x=(1+sqrt(29))/4 ,x=(1-sqrt(29))/4

Find the zeros of 4x^2-2x-7=0

The zeros of 4x^2-2x-7=0 are x=(1+sqrt(29))/4 ,x=(1-sqrt(29))/4

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4 x^{2} - 2 x - 7 = 0

x = \frac{1 + 29}{4}, x = \frac{1 - 29}{4}

Decimal

x = 1.59629 \dots, x = - 1.09629 \dots

Solution steps

4 x^{2} - 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 2)^{2} - 4 \cdot 4 (- 7) = 229

x_{1, 2} = \frac{- ( - 2 ) \pm 2 29}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 29}{2 \cdot 4}, x_{2} = \frac{- ( - 2 ) - 2 29}{2 \cdot 4}

x = \frac{- ( - 2 ) + 2 29}{2 \cdot 4} : \frac{1 + 29}{4}

x = \frac{- ( - 2 ) - 2 29}{2 \cdot 4} : \frac{1 - 29}{4}

The solutions to the quadratic equation are:

x = \frac{1 + 29}{4}, x = \frac{1 - 29}{4}

x^{2} - 23 x + 22

0 = 0.012 x^{2} - 0.593 x - 14.275

- 5 (v + 4) + 36 \leq 5 (3 - v)

x^{2} + 2.5 x + 60 = 0

14 - 46

What are the solutions to the equation 4x^2-2x-7=0 ?
The solutions to the equation 4x^2-2x-7=0 are x=(1+sqrt(29))/4 ,x=(1-sqrt(29))/4
Find the zeros of 4x^2-2x-7=0
The zeros of 4x^2-2x-7=0 are x=(1+sqrt(29))/4 ,x=(1-sqrt(29))/4