What is |x+3|+|x-2|-|x-1|<= 4 ?

The solution to |x+3|+|x-2|-|x-1|<= 4 is -6<= x<= 0\lor x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

|x+3|+|x-2|-|x-1|<= 4

∣ x + 3 ∣ + ∣ x - 2 ∣ - ∣ x - 1 ∣ \leq 4

- 6 \leq x \leq 0 or x = 2

Interval Notation

[- 6, 0] \cup x = 2

Solution steps

∣ x + 3 ∣ + ∣ x - 2 ∣ - ∣ x - 1 ∣ \leq 4

Find positive and negative intervals

x < - 3, - 3 \leq x < 1, 1 \leq x < 2, x \geq 2

Solve the inequality for each interval

- 6 \leq x < - 3 or - 3 \leq x \leq 0 or No Solution or x = 2

Merge Overlapping Intervals

- 6 \leq x \leq 0 or x = 2

\frac{8}{9 x} + 5 < - 3

x^{3} - 3 x^{2} - 6 x + 8

b x + b z + 6 x + 6 z

x^{2} - 2 = x

x - 6 \geq 0

What is |x+3|+|x-2|-|x-1|<= 4 ?
The solution to |x+3|+|x-2|-|x-1|<= 4 is -6<= x<= 0\lor x=2