What are the solutions to the equation n^2-2n-3=0 ?

The solutions to the equation n^2-2n-3=0 are n=3,n=-1

Find the zeros of n^2-2n-3=0

The zeros of n^2-2n-3=0 are n=3,n=-1

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n^{2} - 2 n - 3 = 0

n = 3, n = - 1

Solution steps

n^{2} - 2 n - 3 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

n_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, n_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

n = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

n = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

n = 3, n = - 1

- 3 p^{2} - 10 p - 3

5 (10 - 3)

- 40 (\frac{2 ( 10 b + 23 )}{25}) + 48 b = 17.6

1 x^{2} + 2 x + 1 = 0

2 - x < 3 x + 1 < 10 x

What are the solutions to the equation n^2-2n-3=0 ?
The solutions to the equation n^2-2n-3=0 are n=3,n=-1
Find the zeros of n^2-2n-3=0
The zeros of n^2-2n-3=0 are n=3,n=-1