What is (8x^{-3}y)/(24y^{-4)x^2} ?

The solution to (8x^{-3}y)/(24y^{-4)x^2} is (y^5)/(3x^5)

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simplify (8x^{-3}y)/(24y^{-4)x^2}

simplify

\frac{8 x ^{- 3} y}{24 y ^{- 4} x ^{2}}

\frac{y ^{5}}{3 x ^{5}}

Solution steps

\frac{8 x ^{- 3} y}{24 y ^{- 4} x ^{2}}

Factor the number:

24 = 8 \cdot 3

= \frac{8 x ^{- 3} y}{8 \cdot 3 y ^{- 4} x ^{2}}

Cancel the common factor:

8

= \frac{x ^{- 3} y}{3 y ^{- 4} x ^{2}}

Simplify

\frac{y}{y ^{- 4}} : y^{5}

= \frac{x ^{- 3} y ^{5}}{3 x ^{2}}

Simplify

\frac{x ^{- 3}}{x ^{2}} : \frac{1}{x ^{5}}

= \frac{y ^{5}}{3 x ^{5}}

- 4 + x \leq 2 (x - 5)

x^{4} + 3 x^{3} - 4 x^{2} - 12 x

\frac{1}{2} \cdot 98

- 3 x + 40 = 10

y^{\frac{7}{5}} \times y^{5}

What is (8x^{-3}y)/(24y^{-4)x^2} ?
The solution to (8x^{-3}y)/(24y^{-4)x^2} is (y^5)/(3x^5)