What is (3/2)^{-2}(2/3)(3/4)^{-1} ?

The solution to (3/2)^{-2}(2/3)(3/4)^{-1} is 32/81

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simplify (3/2)^{-2}(2/3)(3/4)^{-1}

simplify

(\frac{3}{2})^{- 2} (\frac{2}{3}) (\frac{3}{4})^{- 1}

\frac{32}{81}

Decimal Notation

0.39506 \dots

Solution steps

(\frac{3}{2})^{- 2} (\frac{2}{3}) (\frac{3}{4})^{- 1}

Apply rule:

(a) = a

(\frac{2}{3}) = \frac{2}{3}

= (\frac{3}{2})^{- 2} \frac{2}{3} (\frac{3}{4})^{- 1}

(\frac{3}{2})^{- 2} = \frac{4}{9}

= \frac{4}{9} \cdot \frac{2}{3} (\frac{3}{4})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(\frac{3}{4})^{- 1} = \frac{1}{\frac{3}{4}}

= \frac{4}{9} \cdot \frac{2}{3} \cdot \frac{1}{\frac{3}{4}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{4}{9} \cdot \frac{2}{3} \cdot \frac{4}{3}

\frac{4}{9} \cdot \frac{2}{3} \cdot \frac{4}{3} = \frac{32}{81}

= \frac{32}{81}

\frac{n !}{3 ! ( n - 3 ) !}

\frac{y + 5}{2} - \frac{y - 2}{4} = \frac{y + 7}{3} + 1

- \frac{1}{2} x \leq - \frac{3}{4} + \frac{2}{5} x

(x + 7)^{2} = 28

12 8^{\frac{3}{7}}

What is (3/2)^{-2}(2/3)(3/4)^{-1} ?
The solution to (3/2)^{-2}(2/3)(3/4)^{-1} is 32/81