What are the solutions to the equation -x^2+x=2x^2+x ?

The solutions to the equation -x^2+x=2x^2+x are x=0

Find the zeros of -x^2+x=2x^2+x

The zeros of -x^2+x=2x^2+x are x=0

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- x^{2} + x = 2 x^{2} + x

x = 0

Solution steps

- x^{2} + x = 2 x^{2} + x

Move

x

to the left side

- x^{2} = 2 x^{2}

Move

2 x^{2}

to the left side

- 3 x^{2} = 0

Divide both sides by

- 3

x = 0

\frac{a ^{- 2}}{2 a b ^{0}}

3 x + 2 = 2

5 (4)^{\frac{1}{4}} + 15 (4)^{\frac{1}{2}} + 3

f (y) = y^{2} - 12

x + 2 < 0

What are the solutions to the equation -x^2+x=2x^2+x ?
The solutions to the equation -x^2+x=2x^2+x are x=0
Find the zeros of -x^2+x=2x^2+x
The zeros of -x^2+x=2x^2+x are x=0