What are the solutions to the equation 5h^2+18h+4=7h-h^2 ?

The solutions to the equation 5h^2+18h+4=7h-h^2 are h=-1/2 ,h=-4/3

Find the zeros of 5h^2+18h+4=7h-h^2

The zeros of 5h^2+18h+4=7h-h^2 are h=-1/2 ,h=-4/3

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5 h^{2} + 18 h + 4 = 7 h - h^{2}

h = - \frac{1}{2}, h = - \frac{4}{3}

Decimal Notation

h = - 0.5, h = - 1.33333 \dots

Solution steps

5 h^{2} + 18 h + 4 = 7 h - h^{2}

Move

h^{2}

to the left side

6 h^{2} + 18 h + 4 = 7 h

Move

7 h

to the left side

6 h^{2} + 11 h + 4 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 6 \cdot 4}{2 \cdot 6}

1 1^{2} - 4 \cdot 6 \cdot 4 = 5

h_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 6}

Separate the solutions

h_{1} = \frac{- 11 + 5}{2 \cdot 6}, h_{2} = \frac{- 11 - 5}{2 \cdot 6}

h = \frac{- 11 + 5}{2 \cdot 6} : - \frac{1}{2}

h = \frac{- 11 - 5}{2 \cdot 6} : - \frac{4}{3}

The solutions to the quadratic equation are:

h = - \frac{1}{2}, h = - \frac{4}{3}

∣ m ∣ > 3

1 = 2 x - 3

\frac{1}{4} (5)^{0}

y^{2} - 2 y

\frac{16}{9} x^{2} - 81 y^{4}

What are the solutions to the equation 5h^2+18h+4=7h-h^2 ?
The solutions to the equation 5h^2+18h+4=7h-h^2 are h=-1/2 ,h=-4/3
Find the zeros of 5h^2+18h+4=7h-h^2
The zeros of 5h^2+18h+4=7h-h^2 are h=-1/2 ,h=-4/3