What are the solutions to the equation 3x^2-7x+9=-9 ?

The solutions to the equation 3x^2-7x+9=-9 are x= 7/6+i(sqrt(167))/6 ,x= 7/6-i(sqrt(167))/6

Find the zeros of 3x^2-7x+9=-9

The zeros of 3x^2-7x+9=-9 are x= 7/6+i(sqrt(167))/6 ,x= 7/6-i(sqrt(167))/6

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3 x^{2} - 7 x + 9 = - 9

x = \frac{7}{6} + i \frac{167}{6}, x = \frac{7}{6} - i \frac{167}{6}

Solution steps

3 x^{2} - 7 x + 9 = - 9

Move

9

to the left side

3 x^{2} - 7 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 18}{2 \cdot 3}

Simplify

(- 7)^{2} - 4 \cdot 3 \cdot 18 : 167 i

x_{1, 2} = \frac{- ( - 7 ) \pm 167 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 167 i}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 167 i}{2 \cdot 3}

x = \frac{- ( - 7 ) + 167 i}{2 \cdot 3} : \frac{7}{6} + i \frac{167}{6}

x = \frac{- ( - 7 ) - 167 i}{2 \cdot 3} : \frac{7}{6} - i \frac{167}{6}

The solutions to the quadratic equation are:

x = \frac{7}{6} + i \frac{167}{6}, x = \frac{7}{6} - i \frac{167}{6}

5 x + 7 > 17

\frac{7.2}{7.5} = \frac{x}{5}

7 - 2 x = 3

2 (2)

- 16 t^{2} + 14 t + 36

What are the solutions to the equation 3x^2-7x+9=-9 ?
The solutions to the equation 3x^2-7x+9=-9 are x= 7/6+i(sqrt(167))/6 ,x= 7/6-i(sqrt(167))/6
Find the zeros of 3x^2-7x+9=-9
The zeros of 3x^2-7x+9=-9 are x= 7/6+i(sqrt(167))/6 ,x= 7/6-i(sqrt(167))/6