What are the solutions to the equation 3x^2+6x-3=0 ?

The solutions to the equation 3x^2+6x-3=0 are x=-1+sqrt(2),x=-1-sqrt(2)

Find the zeros of 3x^2+6x-3=0

The zeros of 3x^2+6x-3=0 are x=-1+sqrt(2),x=-1-sqrt(2)

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3 x^{2} + 6 x - 3 = 0

x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

3 x^{2} + 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 3) = 62

x_{1, 2} = \frac{- 6 \pm 6 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 6 2}{2 \cdot 3}, x_{2} = \frac{- 6 - 6 2}{2 \cdot 3}

x = \frac{- 6 + 6 2}{2 \cdot 3} : - 1 + 2

x = \frac{- 6 - 6 2}{2 \cdot 3} : - 1 - 2

The solutions to the quadratic equation are:

x = - 1 + 2, x = - 1 - 2

- 2 (12 x + 13) \leq - 5 (13 x + 7)

4^{2} + 4

410

20 x^{2} - 27 x = - 14

lo g_{b} (\frac{x ^{3} y}{z ^{5}})

What are the solutions to the equation 3x^2+6x-3=0 ?
The solutions to the equation 3x^2+6x-3=0 are x=-1+sqrt(2),x=-1-sqrt(2)
Find the zeros of 3x^2+6x-3=0
The zeros of 3x^2+6x-3=0 are x=-1+sqrt(2),x=-1-sqrt(2)