What are the solutions to the equation x^2+6x+19=0 ?

The solutions to the equation x^2+6x+19=0 are x=-3+sqrt(10)i,x=-3-sqrt(10)i

Find the zeros of x^2+6x+19=0

The zeros of x^2+6x+19=0 are x=-3+sqrt(10)i,x=-3-sqrt(10)i

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x^{2} + 6 x + 19 = 0

x = - 3 + 10 i, x = - 3 - 10 i

Solution steps

x^{2} + 6 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 19 : 210 i

x_{1, 2} = \frac{- 6 \pm 2 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 10 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 10 i}{2 \cdot 1}

x = \frac{- 6 + 2 10 i}{2 \cdot 1} : - 3 + 10 i

x = \frac{- 6 - 2 10 i}{2 \cdot 1} : - 3 - 10 i

The solutions to the quadratic equation are:

x = - 3 + 10 i, x = - 3 - 10 i

10 + 9 j \geq 1

2 = \frac{2 v}{7} - 8

3 + 9 x = 11 x - 7

x^{2} + 9 x + 35 = 0

- ∣ x - 11 ∣ > 3

What are the solutions to the equation x^2+6x+19=0 ?
The solutions to the equation x^2+6x+19=0 are x=-3+sqrt(10)i,x=-3-sqrt(10)i
Find the zeros of x^2+6x+19=0
The zeros of x^2+6x+19=0 are x=-3+sqrt(10)i,x=-3-sqrt(10)i