What are the solutions to the equation r^2-5r+6=0 ?

The solutions to the equation r^2-5r+6=0 are r=3,r=2

Find the zeros of r^2-5r+6=0

The zeros of r^2-5r+6=0 are r=3,r=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} - 5 r + 6 = 0

r = 3, r = 2

Solution steps

r^{2} - 5 r + 6 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

r_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, r_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

r = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

r = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

r = 3, r = 2

\frac{x y}{2 b ^{2}} x^{4} b

\frac{1}{3} \cdot \frac{1}{3}

x + 3 > 4

3 x^{2} - 11 x - 4 = 0

18 (b - 1) + 2 = 2 (9 b - 8)

What are the solutions to the equation r^2-5r+6=0 ?
The solutions to the equation r^2-5r+6=0 are r=3,r=2
Find the zeros of r^2-5r+6=0
The zeros of r^2-5r+6=0 are r=3,r=2