What are the solutions to the equation r^2+6sqrt(2)r+18=0 ?

The solutions to the equation r^2+6sqrt(2)r+18=0 are r=-3sqrt(2)

Find the zeros of r^2+6sqrt(2)r+18=0

The zeros of r^2+6sqrt(2)r+18=0 are r=-3sqrt(2)

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r^{2} + 62 r + 18 = 0

r = - 32

Decimal Notation

r = - 4.24264 \dots

Solution steps

r^{2} + 62 r + 18 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 6 2 \pm ( 6 2 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(62)^{2} - 4 \cdot 1 \cdot 18 = 0

r_{1, 2} = \frac{- 6 2 \pm 0}{2 \cdot 1}

r = \frac{- 6 2}{2 \cdot 1}

\frac{- 6 2}{2 \cdot 1} = - 32

r = - 32

The solution to the quadratic equation is:

r = - 32

lo g_{5} (5)

- \frac{2}{3} x - \frac{21}{4} = \frac{27}{4}

7 z^{2} - 2 z - 5

x^{\frac{1}{2}} \cdot x^{2}

\frac{v ^{- 8}}{v ^{7}}

What are the solutions to the equation r^2+6sqrt(2)r+18=0 ?
The solutions to the equation r^2+6sqrt(2)r+18=0 are r=-3sqrt(2)
Find the zeros of r^2+6sqrt(2)r+18=0
The zeros of r^2+6sqrt(2)r+18=0 are r=-3sqrt(2)