What are the solutions to the equation 12^2+10^2=x^2 ?

The solutions to the equation 12^2+10^2=x^2 are x=2sqrt(61),x=-2sqrt(61)

Find the zeros of 12^2+10^2=x^2

The zeros of 12^2+10^2=x^2 are x=2sqrt(61),x=-2sqrt(61)

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1 2^{2} + 1 0^{2} = x^{2}

x = 261, x = - 261

Decimal Notation

x = 15.62049 \dots, x = - 15.62049 \dots

Solution steps

1 2^{2} + 1 0^{2} = x^{2}

Switch sides

x^{2} = 1 2^{2} + 1 0^{2}

Simplify

1 2^{2} + 1 0^{2} : 244

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 244, x = - 244

244 = 261

- 244 = - 261

x = 261, x = - 261

8 x + (- 5 x - 9) = 3 x + [- 5 x - (x + 3)]

x^{2} - x + 7 = 0

x^{2} - 4 x = 2

8 + y < 1

3 (6 x - 10) - 5 (2 - 4 x) = 25 x - 1

What are the solutions to the equation 12^2+10^2=x^2 ?
The solutions to the equation 12^2+10^2=x^2 are x=2sqrt(61),x=-2sqrt(61)
Find the zeros of 12^2+10^2=x^2
The zeros of 12^2+10^2=x^2 are x=2sqrt(61),x=-2sqrt(61)