What are the solutions to the equation -10q^2+2600q-150000=0 ?

The solutions to the equation -10q^2+2600q-150000=0 are q=10(13-sqrt(19)),q=10(13+sqrt(19))

Find the zeros of -10q^2+2600q-150000=0

The zeros of -10q^2+2600q-150000=0 are q=10(13-sqrt(19)),q=10(13+sqrt(19))

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- 10 q^{2} + 2600 q - 150000 = 0

q = 10 (13 - 19), q = 10 (13 + 19)

Decimal Notation

q = 86.41101 \dots, q = 173.58898 \dots

Solution steps

- 10 q^{2} + 2600 q - 150000 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 2600 \pm 260 0 ^{2} - 4 ( - 10 ) ( - 150000 )}{2 ( - 10 )}

260 0^{2} - 4 (- 10) (- 150000) = 20019

q_{1, 2} = \frac{- 2600 \pm 200 19}{2 ( - 10 )}

Separate the solutions

q_{1} = \frac{- 2600 + 200 19}{2 ( - 10 )}, q_{2} = \frac{- 2600 - 200 19}{2 ( - 10 )}

q = \frac{- 2600 + 200 19}{2 ( - 10 )} : 10 (13 - 19)

q = \frac{- 2600 - 200 19}{2 ( - 10 )} : 10 (13 + 19)

The solutions to the quadratic equation are:

q = 10 (13 - 19), q = 10 (13 + 19)

4320

\frac{1}{2} (2 + x) \leq 2 (x + 3)

0 < \frac{x - 5}{x - 1}

10 x + 5 = 175

7 x^{2} - 20 x + 12

What are the solutions to the equation -10q^2+2600q-150000=0 ?
The solutions to the equation -10q^2+2600q-150000=0 are q=10(13-sqrt(19)),q=10(13+sqrt(19))
Find the zeros of -10q^2+2600q-150000=0
The zeros of -10q^2+2600q-150000=0 are q=10(13-sqrt(19)),q=10(13+sqrt(19))