What are the solutions to the equation 5y^2+5y=2 ?

The solutions to the equation 5y^2+5y=2 are y=(-5+sqrt(65))/(10),y=(-5-sqrt(65))/(10)

Find the zeros of 5y^2+5y=2

The zeros of 5y^2+5y=2 are y=(-5+sqrt(65))/(10),y=(-5-sqrt(65))/(10)

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5 y^{2} + 5 y = 2

y = \frac{- 5 + 65}{10}, y = \frac{- 5 - 65}{10}

Decimal Notation

y = 0.30622 \dots, y = - 1.30622 \dots

Solution steps

5 y^{2} + 5 y = 2

Move

2

to the left side

5 y^{2} + 5 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

5^{2} - 4 \cdot 5 (- 2) = 65

y_{1, 2} = \frac{- 5 \pm 65}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 5 + 65}{2 \cdot 5}, y_{2} = \frac{- 5 - 65}{2 \cdot 5}

y = \frac{- 5 + 65}{2 \cdot 5} : \frac{- 5 + 65}{10}

y = \frac{- 5 - 65}{2 \cdot 5} : \frac{- 5 - 65}{10}

The solutions to the quadratic equation are:

y = \frac{- 5 + 65}{10}, y = \frac{- 5 - 65}{10}

3 (x + 2) = x + 2

\frac{2}{5} t = \frac{12}{25}

2 \cdot (x - 3) < 21

I = 100 \cdot e^{- 59.7 \cdot 0.05}

\frac{5 - 2}{- 2 - 1}

What are the solutions to the equation 5y^2+5y=2 ?
The solutions to the equation 5y^2+5y=2 are y=(-5+sqrt(65))/(10),y=(-5-sqrt(65))/(10)
Find the zeros of 5y^2+5y=2
The zeros of 5y^2+5y=2 are y=(-5+sqrt(65))/(10),y=(-5-sqrt(65))/(10)