What are the solutions to the equation 3(x^2-2)+18=0 ?

The solutions to the equation 3(x^2-2)+18=0 are x=2i,x=-2i

Find the zeros of 3(x^2-2)+18=0

The zeros of 3(x^2-2)+18=0 are x=2i,x=-2i

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3 (x^{2} - 2) + 18 = 0

x = 2 i, x = - 2 i

Solution steps

3 (x^{2} - 2) + 18 = 0

Move

18

to the right side

3 (x^{2} - 2) = - 18

Divide both sides by

3

x^{2} - 2 = - 6

Move

2

to the right side

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

x^{\frac{2}{3}} \cdot x^{\frac{2}{3}}

\frac{3}{5} \cdot 2

4 (u + 1) - u = 3 (u - 1) + 3

5 (x + 3) = 2 x

\frac{( 130 ) ( 0.0 7 ^{1.4} )}{80} = x

What are the solutions to the equation 3(x^2-2)+18=0 ?
The solutions to the equation 3(x^2-2)+18=0 are x=2i,x=-2i
Find the zeros of 3(x^2-2)+18=0
The zeros of 3(x^2-2)+18=0 are x=2i,x=-2i