What are the solutions to the equation x^2+7x-12=0 ?

The solutions to the equation x^2+7x-12=0 are x=(-7+sqrt(97))/2 ,x=(-7-sqrt(97))/2

Find the zeros of x^2+7x-12=0

The zeros of x^2+7x-12=0 are x=(-7+sqrt(97))/2 ,x=(-7-sqrt(97))/2

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x^{2} + 7 x - 12 = 0

x = \frac{- 7 + 97}{2}, x = \frac{- 7 - 97}{2}

Decimal Notation

x = 1.42442 \dots, x = - 8.42442 \dots

Solution steps

x^{2} + 7 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 12) = 97

x_{1, 2} = \frac{- 7 \pm 97}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 97}{2 \cdot 1}, x_{2} = \frac{- 7 - 97}{2 \cdot 1}

x = \frac{- 7 + 97}{2 \cdot 1} : \frac{- 7 + 97}{2}

x = \frac{- 7 - 97}{2 \cdot 1} : \frac{- 7 - 97}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 97}{2}, x = \frac{- 7 - 97}{2}

\frac{1}{4} a + \frac{2}{3} a

\frac{1}{8} + \frac{3}{8}

9 r^{2} + 3 r - 30

\frac{1}{2} x + 5 = - \frac{3}{4} x - 6

\frac{x + 4}{x + 12} > 10

What are the solutions to the equation x^2+7x-12=0 ?
The solutions to the equation x^2+7x-12=0 are x=(-7+sqrt(97))/2 ,x=(-7-sqrt(97))/2
Find the zeros of x^2+7x-12=0
The zeros of x^2+7x-12=0 are x=(-7+sqrt(97))/2 ,x=(-7-sqrt(97))/2