What are the solutions to the equation 7x^2+2x+8=0 ?

The solutions to the equation 7x^2+2x+8=0 are x=-1/7+i(sqrt(55))/7 ,x=-1/7-i(sqrt(55))/7

Find the zeros of 7x^2+2x+8=0

The zeros of 7x^2+2x+8=0 are x=-1/7+i(sqrt(55))/7 ,x=-1/7-i(sqrt(55))/7

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7 x^{2} + 2 x + 8 = 0

x = - \frac{1}{7} + i \frac{55}{7}, x = - \frac{1}{7} - i \frac{55}{7}

Solution steps

7 x^{2} + 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 7 \cdot 8}{2 \cdot 7}

Simplify

2^{2} - 4 \cdot 7 \cdot 8 : 255 i

x_{1, 2} = \frac{- 2 \pm 2 55 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 2 + 2 55 i}{2 \cdot 7}, x_{2} = \frac{- 2 - 2 55 i}{2 \cdot 7}

x = \frac{- 2 + 2 55 i}{2 \cdot 7} : - \frac{1}{7} + i \frac{55}{7}

x = \frac{- 2 - 2 55 i}{2 \cdot 7} : - \frac{1}{7} - i \frac{55}{7}

The solutions to the quadratic equation are:

x = - \frac{1}{7} + i \frac{55}{7}, x = - \frac{1}{7} - i \frac{55}{7}

7 x - 6 (3 x - 5) < 5 x - 3 (4 x + 8)

x^{3} - 11 x^{2} + 23 x + 35

(\frac{7}{3} - \frac{2}{5}) \div \frac{2}{3}

\frac{2}{9} - \frac{8}{9}

7 x - 14 = 21

What are the solutions to the equation 7x^2+2x+8=0 ?
The solutions to the equation 7x^2+2x+8=0 are x=-1/7+i(sqrt(55))/7 ,x=-1/7-i(sqrt(55))/7
Find the zeros of 7x^2+2x+8=0
The zeros of 7x^2+2x+8=0 are x=-1/7+i(sqrt(55))/7 ,x=-1/7-i(sqrt(55))/7