What are the solutions to the equation 4x^2+x-9=0 ?

The solutions to the equation 4x^2+x-9=0 are x=(-1+sqrt(145))/8 ,x=(-1-sqrt(145))/8

Find the zeros of 4x^2+x-9=0

The zeros of 4x^2+x-9=0 are x=(-1+sqrt(145))/8 ,x=(-1-sqrt(145))/8

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4 x^{2} + x - 9 = 0

x = \frac{- 1 + 145}{8}, x = \frac{- 1 - 145}{8}

Decimal Notation

x = 1.38019 \dots, x = - 1.63019 \dots

Solution steps

4 x^{2} + x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 9) = 145

x_{1, 2} = \frac{- 1 \pm 145}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 145}{2 \cdot 4}, x_{2} = \frac{- 1 - 145}{2 \cdot 4}

x = \frac{- 1 + 145}{2 \cdot 4} : \frac{- 1 + 145}{8}

x = \frac{- 1 - 145}{2 \cdot 4} : \frac{- 1 - 145}{8}

The solutions to the quadratic equation are:

x = \frac{- 1 + 145}{8}, x = \frac{- 1 - 145}{8}

\frac{5}{3 - i}

lo g_{2} (8) - lo g_{2} (4)

6 x = 3 x + 12

15 \cdot \frac{2}{3}

(\frac{4}{3})^{- 1}

What are the solutions to the equation 4x^2+x-9=0 ?
The solutions to the equation 4x^2+x-9=0 are x=(-1+sqrt(145))/8 ,x=(-1-sqrt(145))/8
Find the zeros of 4x^2+x-9=0
The zeros of 4x^2+x-9=0 are x=(-1+sqrt(145))/8 ,x=(-1-sqrt(145))/8