What is 5/(x-9)< 2/(x+2) ?

The solution to 5/(x-9)< 2/(x+2) is x<-28/3 \lor-2<x<9

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5/(x-9)< 2/(x+2)

\frac{5}{x - 9} < \frac{2}{x + 2}

x < - \frac{28}{3} or - 2 < x < 9

Interval Notation

(- \infty, - \frac{28}{3}) \cup (- 2, 9)

Decimal Notation

x < - 9.33333 \dots or - 2 < x < 9

Solution steps

\frac{5}{x - 9} < \frac{2}{x + 2}

Rewrite in standard form

\frac{3 x + 28}{( x - 9 ) ( x + 2 )} < 0

Identify the intervals

x < - \frac{28}{3} or - 2 < x < 9

(x + 3)^{3} + y^{3}

\frac{1}{25}

2 ∣ x + 5 ∣ + 3 < 25

- 5 x^{2} + 13 x - 125 = 0

∣ x - 2 ∣ = 4

What is 5/(x-9)< 2/(x+2) ?
The solution to 5/(x-9)< 2/(x+2) is x<-28/3 \lor-2<x<9