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Popular >

4|x-1|-8<= 40

Solution

4 ∣ x - 1 ∣ - 8 \leq 40

Solution

- 11 \leq x \leq 13

+1

Solution steps

4 ∣ x - 1 ∣ - 8 \leq 40

Move

8

to the right side

4 ∣ x - 1 ∣ \leq 48

Divide both sides by

4

∣ x - 1 ∣ \leq 12

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 12 \leq x - 1 \leq 12

x - 1 \geq - 12 and x - 1 \leq 12

x \geq - 11 and x \leq 13

Merge Overlapping Intervals

- 11 \leq x \leq 13

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Frequently Asked Questions (FAQ)

What is 4|x-1|-8<= 40 ?
The solution to 4|x-1|-8<= 40 is -11<= x<= 13