What are the solutions to the equation x^2+8x-84=0 ?

The solutions to the equation x^2+8x-84=0 are x=6,x=-14

Find the zeros of x^2+8x-84=0

The zeros of x^2+8x-84=0 are x=6,x=-14

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x^{2} + 8 x - 84 = 0

x = 6, x = - 14

Solution steps

x^{2} + 8 x - 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 84 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 84) = 20

x_{1, 2} = \frac{- 8 \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 20}{2 \cdot 1}, x_{2} = \frac{- 8 - 20}{2 \cdot 1}

x = \frac{- 8 + 20}{2 \cdot 1} : 6

x = \frac{- 8 - 20}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = 6, x = - 14

0.0 2^{2}

2 x + 6 = 2

x^{2} - 10 x y - 39 y^{2}

(81)^{\frac{1}{2}}

45 pq - 27 q - 50 p + 30

What are the solutions to the equation x^2+8x-84=0 ?
The solutions to the equation x^2+8x-84=0 are x=6,x=-14
Find the zeros of x^2+8x-84=0
The zeros of x^2+8x-84=0 are x=6,x=-14