What are the solutions to the equation x^2+9x+81/4 =0 ?

The solutions to the equation x^2+9x+81/4 =0 are x=-9/2

Find the zeros of x^2+9x+81/4 =0

The zeros of x^2+9x+81/4 =0 are x=-9/2

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x^{2} + 9 x + \frac{81}{4} = 0

x = - \frac{9}{2}

Decimal Notation

x = - 4.5

Solution steps

x^{2} + 9 x + \frac{81}{4} = 0

Multiply both sides by

4

4 x^{2} + 36 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 4 \cdot 81}{2 \cdot 4}

3 6^{2} - 4 \cdot 4 \cdot 81 = 0

x_{1, 2} = \frac{- 36 \pm 0}{2 \cdot 4}

x = \frac{- 36}{2 \cdot 4}

\frac{- 36}{2 \cdot 4} = - \frac{9}{2}

x = - \frac{9}{2}

The solution to the quadratic equation is:

x = - \frac{9}{2}

k^{2} + 13 k + 12

x - 3 = (10 x - 54) \frac{1}{2}

- \frac{63}{16} + 8

- 4 + \frac{p}{3} \leq - 3

1.5

What are the solutions to the equation x^2+9x+81/4 =0 ?
The solutions to the equation x^2+9x+81/4 =0 are x=-9/2
Find the zeros of x^2+9x+81/4 =0
The zeros of x^2+9x+81/4 =0 are x=-9/2