What are the solutions to the equation -x^2-2x=-3 ?

The solutions to the equation -x^2-2x=-3 are x=-3,x=1

Find the zeros of -x^2-2x=-3

The zeros of -x^2-2x=-3 are x=-3,x=1

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- x^{2} - 2 x = - 3

x = - 3, x = 1

Solution steps

- x^{2} - 2 x = - 3

Move

3

to the left side

- x^{2} - 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 3 = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 4}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 4}{2 ( - 1 )} : - 3

x = \frac{- ( - 2 ) - 4}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = - 3, x = 1

2 d^{4} + 6 d^{3} - 18 d^{2} - 54 d

(- x)^{4}

e^{\frac{- 3}{2}}

\frac{x}{x - 9} > 6 x - 2

4 x - 3 = x + 9

What are the solutions to the equation -x^2-2x=-3 ?
The solutions to the equation -x^2-2x=-3 are x=-3,x=1
Find the zeros of -x^2-2x=-3
The zeros of -x^2-2x=-3 are x=-3,x=1