What are the solutions to the equation 6x^2+29x-5=0 ?

The solutions to the equation 6x^2+29x-5=0 are x= 1/6 ,x=-5

Find the zeros of 6x^2+29x-5=0

The zeros of 6x^2+29x-5=0 are x= 1/6 ,x=-5

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6 x^{2} + 29 x - 5 = 0

x = \frac{1}{6}, x = - 5

Decimal Notation

x = 0.16666 \dots, x = - 5

Solution steps

6 x^{2} + 29 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 29 \pm 2 9 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

2 9^{2} - 4 \cdot 6 (- 5) = 31

x_{1, 2} = \frac{- 29 \pm 31}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 29 + 31}{2 \cdot 6}, x_{2} = \frac{- 29 - 31}{2 \cdot 6}

x = \frac{- 29 + 31}{2 \cdot 6} : \frac{1}{6}

x = \frac{- 29 - 31}{2 \cdot 6} : - 5

The solutions to the quadratic equation are:

x = \frac{1}{6}, x = - 5

\frac{- 4 ( r ^{4} t ^{- 2} ) ^{- 1}}{4 r ^{2} t ^{4}}

9 x^{2} + 6 x = 3

x^{2} + 2 x + 1 > 9

50 \cdot 9.8

\frac{1}{2} a + \frac{3}{2} b

What are the solutions to the equation 6x^2+29x-5=0 ?
The solutions to the equation 6x^2+29x-5=0 are x= 1/6 ,x=-5
Find the zeros of 6x^2+29x-5=0
The zeros of 6x^2+29x-5=0 are x= 1/6 ,x=-5