What is (x+1)/(x+2)>= (x-4)/(2x-3) ?

The solution to (x+1)/(x+2)>= (x-4)/(2x-3) is x 3/2

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(x+1)/(x+2)>= (x-4)/(2x-3)

\frac{x + 1}{x + 2} \geq \frac{x - 4}{2 x - 3}

x < - 2 or x > \frac{3}{2}

Interval Notation

(- \infty, - 2) \cup (\frac{3}{2}, \infty)

Decimal Notation

x < - 2 or x > 1.5

Solution steps

\frac{x + 1}{x + 2} \geq \frac{x - 4}{2 x - 3}

Rewrite in standard form

\frac{x ^{2} + x + 5}{( x + 2 ) ( 2 x - 3 )} \geq 0

Identify the intervals

x < - 2 or x > \frac{3}{2}

\frac{x + 27}{x + 6} \leq 9

- \frac{4}{- \frac{1}{2}}

3 x - 3 (x + 1) = 3

- 1 \leq 2 n + 4 - 5

(x - 3) (x - 5) (x - 6) \geq 0

What is (x+1)/(x+2)>= (x-4)/(2x-3) ?
The solution to (x+1)/(x+2)>= (x-4)/(2x-3) is x<-2\lor x> 3/2