What is (19-4i}{2-5i}-\frac{3+2i)/i ?

The solution to (19-4i}{2-5i}-\frac{3+2i)/i is 6i

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simplify (19-4i}{2-5i}-\frac{3+2i)/i

simplify

\frac{19 - 4 i}{2 - 5 i} - \frac{3 + 2 i}{i}

6 i

Solution steps

\frac{19 - 4 i}{2 - 5 i} - \frac{3 + 2 i}{i}

\frac{19 - 4 i}{2 - 5 i} = 2 + 3 i

\frac{3 + 2 i}{i} = - 3 i + 2

= 2 + 3 i - (- 3 i + 2)

Expand

- (- 3 i + 2) : 3 i - 2

= 2 + 3 i + 3 i - 2

Group like terms

= 3 i + 3 i + 2 - 2

Add similar elements:

3 i + 3 i = 6 i

= 6 i + 2 - 2

Subtract the numbers:

2 - 2 = 0

= 6 i

\frac{i}{- i}

y^{3} - 125 z^{3}

3 (v + 2) + 2 v = 7 (v - 1) + 9

(2 x^{- \frac{1}{2}})^{4}

x^{2} + 10 x - 56

What is (19-4i}{2-5i}-\frac{3+2i)/i ?
The solution to (19-4i}{2-5i}-\frac{3+2i)/i is 6i