What is factor 2t^2+9t-11 ?

The solution to factor 2t^2+9t-11 is (t-1)(2t+11)

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factor 2t^2+9t-11

factor

2 t^{2} + 9 t - 11

(t - 1) (2 t + 11)

Solution steps

2 t^{2} + 9 t - 11

Break the expression into groups

= (2 t^{2} - 2 t) + (11 t - 11)

Factor out

2 t

from

2 t^{2} - 2 t : 2 t (t - 1)

Factor out

11

from

11 t - 11 : 11 (t - 1)

= 2 t (t - 1) + 11 (t - 1)

Factor out common term

t - 1

= (t - 1) (2 t + 11)

- (\frac{1}{2})^{- 3}

b^{2} + 2 b - 5 = 0

- 7 x - 1 = - 9 x - 17

\frac{5 x + 25}{x - 1} < 0

2 m^{p} n^{r} + 6 m^{p - 1} n^{r + 1} - 12 m^{p + 1} n^{r - 1}