What are the solutions to the equation (z+7)^2=2 ?

The solutions to the equation (z+7)^2=2 are z=sqrt(2)-7,z=-sqrt(2)-7

Find the zeros of (z+7)^2=2

The zeros of (z+7)^2=2 are z=sqrt(2)-7,z=-sqrt(2)-7

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(z + 7)^{2} = 2

z = 2 - 7, z = - 2 - 7

Decimal Notation

z = - 5.58578 \dots, z = - 8.41421 \dots

Solution steps

(z + 7)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 7 = 2 : z = 2 - 7

Solve

z + 7 = - 2 : z = - 2 - 7

The solutions to the quadratic equation are:

z = 2 - 7, z = - 2 - 7

4 \leq 3 x - 2 < 13

2 y + 4 y = 54

8 x^{2} + 6 x + 1

\frac{3 x}{8} - 5 > \frac{3}{4}

(5 z - 7)^{2} + 64 = 0

What are the solutions to the equation (z+7)^2=2 ?
The solutions to the equation (z+7)^2=2 are z=sqrt(2)-7,z=-sqrt(2)-7
Find the zeros of (z+7)^2=2
The zeros of (z+7)^2=2 are z=sqrt(2)-7,z=-sqrt(2)-7