What are the solutions to the equation 8x^2-2x-1=0 ?

The solutions to the equation 8x^2-2x-1=0 are x= 1/2 ,x=-1/4

Find the zeros of 8x^2-2x-1=0

The zeros of 8x^2-2x-1=0 are x= 1/2 ,x=-1/4

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8 x^{2} - 2 x - 1 = 0

x = \frac{1}{2}, x = - \frac{1}{4}

Decimal Notation

x = 0.5, x = - 0.25

Solution steps

8 x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 8 ( - 1 )}{2 \cdot 8}

(- 2)^{2} - 4 \cdot 8 (- 1) = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 8}, x_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 8}

x = \frac{- ( - 2 ) + 6}{2 \cdot 8} : \frac{1}{2}

x = \frac{- ( - 2 ) - 6}{2 \cdot 8} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{1}{4}

x^{\frac{1}{2}} \cdot 3 x^{2}

4 x^{4} + 5 x^{2} + 1

c - 8 = 16

8 x + 2 > 34

- 1.2 (4)^{2} + 9.6 (4)

What are the solutions to the equation 8x^2-2x-1=0 ?
The solutions to the equation 8x^2-2x-1=0 are x= 1/2 ,x=-1/4
Find the zeros of 8x^2-2x-1=0
The zeros of 8x^2-2x-1=0 are x= 1/2 ,x=-1/4