What are the solutions to the equation 25p+6p^2=-4 ?

The solutions to the equation 25p+6p^2=-4 are p=-1/6 ,p=-4

Find the zeros of 25p+6p^2=-4

The zeros of 25p+6p^2=-4 are p=-1/6 ,p=-4

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25 p + 6 p^{2} = - 4

p = - \frac{1}{6}, p = - 4

Decimal Notation

p = - 0.16666 \dots, p = - 4

Solution steps

25 p + 6 p^{2} = - 4

Move

4

to the left side

25 p + 6 p^{2} + 4 = 0

Write in the standard form

a x^{2} + b x + c = 0

6 p^{2} + 25 p + 4 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 6 \cdot 4}{2 \cdot 6}

2 5^{2} - 4 \cdot 6 \cdot 4 = 23

p_{1, 2} = \frac{- 25 \pm 23}{2 \cdot 6}

Separate the solutions

p_{1} = \frac{- 25 + 23}{2 \cdot 6}, p_{2} = \frac{- 25 - 23}{2 \cdot 6}

p = \frac{- 25 + 23}{2 \cdot 6} : - \frac{1}{6}

p = \frac{- 25 - 23}{2 \cdot 6} : - 4

The solutions to the quadratic equation are:

p = - \frac{1}{6}, p = - 4

- 2 p - 3 = - 19

x^{2} - 3 x + 1 < 5

\frac{3}{1} \cdot \frac{1}{2}

5 x - (4 x - 1) = 2

- 4 \leq x \leq 1

What are the solutions to the equation 25p+6p^2=-4 ?
The solutions to the equation 25p+6p^2=-4 are p=-1/6 ,p=-4
Find the zeros of 25p+6p^2=-4
The zeros of 25p+6p^2=-4 are p=-1/6 ,p=-4