What are the solutions to the equation (2z-20)^2=-12 ?

The solutions to the equation (2z-20)^2=-12 are z=sqrt(3)i+10,z=-sqrt(3)i+10

Find the zeros of (2z-20)^2=-12

The zeros of (2z-20)^2=-12 are z=sqrt(3)i+10,z=-sqrt(3)i+10

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(2 z - 20)^{2} = - 12

z = 3 i + 10, z = - 3 i + 10

Solution steps

(2 z - 20)^{2} = - 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 z - 20 = - 12 : z = 3 i + 10

Solve

2 z - 20 = - - 12 : z = - 3 i + 10

The solutions to the quadratic equation are:

z = 3 i + 10, z = - 3 i + 10

∣ x - 10 ∣ = 8

6 h - 10 h + 2 \geq - 10

(4 x + 7) (x - 1) = (2 x + 1)^{2}

3 5^{2}

- 6 k + 1 = - 2 + 7 k

What are the solutions to the equation (2z-20)^2=-12 ?
The solutions to the equation (2z-20)^2=-12 are z=sqrt(3)i+10,z=-sqrt(3)i+10
Find the zeros of (2z-20)^2=-12
The zeros of (2z-20)^2=-12 are z=sqrt(3)i+10,z=-sqrt(3)i+10