What are the solutions to the equation 10x^2-19x+6=0 ?

The solutions to the equation 10x^2-19x+6=0 are x= 3/2 ,x= 2/5

Find the zeros of 10x^2-19x+6=0

The zeros of 10x^2-19x+6=0 are x= 3/2 ,x= 2/5

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10 x^{2} - 19 x + 6 = 0

x = \frac{3}{2}, x = \frac{2}{5}

Solution steps

10 x^{2} - 19 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 10 \cdot 6}{2 \cdot 10}

(- 19)^{2} - 4 \cdot 10 \cdot 6 = 11

x_{1, 2} = \frac{- ( - 19 ) \pm 11}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 11}{2 \cdot 10}, x_{2} = \frac{- ( - 19 ) - 11}{2 \cdot 10}

x = \frac{- ( - 19 ) + 11}{2 \cdot 10} : \frac{3}{2}

x = \frac{- ( - 19 ) - 11}{2 \cdot 10} : \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{2}{5}

x > 3 and x < 2

x (x + 1) = 420

∣ 2 - 3 x ∣ = 5

16 x^{4} + 8 x^{2} - 3

(x - 4)^{2} = 2 x^{2} - 15 + 22

What are the solutions to the equation 10x^2-19x+6=0 ?
The solutions to the equation 10x^2-19x+6=0 are x= 3/2 ,x= 2/5
Find the zeros of 10x^2-19x+6=0
The zeros of 10x^2-19x+6=0 are x= 3/2 ,x= 2/5