What are the solutions to the equation (x+9)^2=-16 ?

The solutions to the equation (x+9)^2=-16 are x=4i-9,x=-4i-9

Find the zeros of (x+9)^2=-16

The zeros of (x+9)^2=-16 are x=4i-9,x=-4i-9

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(x + 9)^{2} = - 16

x = 4 i - 9, x = - 4 i - 9

Solution steps

(x + 9)^{2} = - 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 9 = - 16 : x = 4 i - 9

Solve

x + 9 = - - 16 : x = - 4 i - 9

The solutions to the quadratic equation are:

x = 4 i - 9, x = - 4 i - 9

- 9 \leq b - 4

\frac{1}{4} \cdot 2 π

(\frac{2 x ^{2}}{5 x ^{3}})^{- 2}

x + 1 = 4

t^{3} - 7 t^{2} + 14 t - 8

What are the solutions to the equation (x+9)^2=-16 ?
The solutions to the equation (x+9)^2=-16 are x=4i-9,x=-4i-9
Find the zeros of (x+9)^2=-16
The zeros of (x+9)^2=-16 are x=4i-9,x=-4i-9