What are the solutions to the equation X^2-X-6=0 ?

The solutions to the equation X^2-X-6=0 are X=3,X=-2

Find the zeros of X^2-X-6=0

The zeros of X^2-X-6=0 are X=3,X=-2

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X^{2} - X - 6 = 0

X = 3, X = - 2

Solution steps

X^{2} - X - 6 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

X_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, X_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

X = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

X = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

X = 3, X = - 2

5 x + 3 x \leq 4 - x

2 a^{3} - a^{2} - 36 a - 45

- 4 p = 3 p + 28

x - 21 < 31

\frac{11}{32} \cdot \frac{180}{π}

What are the solutions to the equation X^2-X-6=0 ?
The solutions to the equation X^2-X-6=0 are X=3,X=-2
Find the zeros of X^2-X-6=0
The zeros of X^2-X-6=0 are X=3,X=-2