What are the solutions to the equation (5n+1)^2+5(5n+1)-6=0 ?

The solutions to the equation (5n+1)^2+5(5n+1)-6=0 are n=0,n=-7/5

Find the zeros of (5n+1)^2+5(5n+1)-6=0

The zeros of (5n+1)^2+5(5n+1)-6=0 are n=0,n=-7/5

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(5 n + 1)^{2} + 5 (5 n + 1) - 6 = 0

n = 0, n = - \frac{7}{5}

Decimal Notation

n = 0, n = - 1.4

Solution steps

(5 n + 1)^{2} + 5 (5 n + 1) - 6 = 0

Expand

(5 n + 1)^{2} + 5 (5 n + 1) - 6 : 25 n^{2} + 35 n

25 n^{2} + 35 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 35 \pm 3 5 ^{2} - 4 \cdot 25 \cdot 0}{2 \cdot 25}

3 5^{2} - 4 \cdot 25 \cdot 0 = 35

n_{1, 2} = \frac{- 35 \pm 35}{2 \cdot 25}

Separate the solutions

n_{1} = \frac{- 35 + 35}{2 \cdot 25}, n_{2} = \frac{- 35 - 35}{2 \cdot 25}

n = \frac{- 35 + 35}{2 \cdot 25} : 0

n = \frac{- 35 - 35}{2 \cdot 25} : - \frac{7}{5}

The solutions to the quadratic equation are:

n = 0, n = - \frac{7}{5}

- \frac{2}{9} - (- \frac{1}{15})

\frac{1}{2} (- 1) + 3

a^{6} + b^{6} - a^{2} b^{4} - a^{4} b^{2}

\frac{4}{5} x = 1

- 5 + \frac{b}{26} = - 6

What are the solutions to the equation (5n+1)^2+5(5n+1)-6=0 ?
The solutions to the equation (5n+1)^2+5(5n+1)-6=0 are n=0,n=-7/5
Find the zeros of (5n+1)^2+5(5n+1)-6=0
The zeros of (5n+1)^2+5(5n+1)-6=0 are n=0,n=-7/5