What are the solutions to the equation 2x^2-24x=-36 ?

The solutions to the equation 2x^2-24x=-36 are x=3(2+sqrt(2)),x=3(2-sqrt(2))

Find the zeros of 2x^2-24x=-36

The zeros of 2x^2-24x=-36 are x=3(2+sqrt(2)),x=3(2-sqrt(2))

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2 x^{2} - 24 x = - 36

x = 3 (2 + 2), x = 3 (2 - 2)

Decimal Notation

x = 10.24264 \dots, x = 1.75735 \dots

Solution steps

2 x^{2} - 24 x = - 36

Move

36

to the left side

2 x^{2} - 24 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 2 \cdot 36}{2 \cdot 2}

(- 24)^{2} - 4 \cdot 2 \cdot 36 = 122

x_{1, 2} = \frac{- ( - 24 ) \pm 12 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12 2}{2 \cdot 2}, x_{2} = \frac{- ( - 24 ) - 12 2}{2 \cdot 2}

x = \frac{- ( - 24 ) + 12 2}{2 \cdot 2} : 3 (2 + 2)

x = \frac{- ( - 24 ) - 12 2}{2 \cdot 2} : 3 (2 - 2)

The solutions to the quadratic equation are:

x = 3 (2 + 2), x = 3 (2 - 2)

2 x - 8 < 0

60 t^{2} + 45 t + 40 t + 30

3 x = 9

x^{3} + 3 x^{2} + 3 x + 2

8 x^{2} - 14 x - 15

What are the solutions to the equation 2x^2-24x=-36 ?
The solutions to the equation 2x^2-24x=-36 are x=3(2+sqrt(2)),x=3(2-sqrt(2))
Find the zeros of 2x^2-24x=-36
The zeros of 2x^2-24x=-36 are x=3(2+sqrt(2)),x=3(2-sqrt(2))