What are the solutions to the equation -2x^2-5x+3=0 ?

The solutions to the equation -2x^2-5x+3=0 are x=-3,x= 1/2

Find the zeros of -2x^2-5x+3=0

The zeros of -2x^2-5x+3=0 are x=-3,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} - 5 x + 3 = 0

x = - 3, x = \frac{1}{2}

Decimal Notation

x = - 3, x = 0.5

Solution steps

- 2 x^{2} - 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

(- 5)^{2} - 4 (- 2) \cdot 3 = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 ( - 2 )}, x_{2} = \frac{- ( - 5 ) - 7}{2 ( - 2 )}

x = \frac{- ( - 5 ) + 7}{2 ( - 2 )} : - 3

x = \frac{- ( - 5 ) - 7}{2 ( - 2 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = - 3, x = \frac{1}{2}

0 = 4 x^{2} + 12 x + 8

18 x^{2} y + 60 x y^{2} + 50 y^{3}

∣ 9 ∣

- 2 - \frac{3}{2}

2^{l o g_{2} (n) + 1}

What are the solutions to the equation -2x^2-5x+3=0 ?
The solutions to the equation -2x^2-5x+3=0 are x=-3,x= 1/2
Find the zeros of -2x^2-5x+3=0
The zeros of -2x^2-5x+3=0 are x=-3,x= 1/2