What are the solutions to the equation 9x^2+18x+18=0 ?

The solutions to the equation 9x^2+18x+18=0 are x=-1+i,x=-1-i

Find the zeros of 9x^2+18x+18=0

The zeros of 9x^2+18x+18=0 are x=-1+i,x=-1-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} + 18 x + 18 = 0

x = - 1 + i, x = - 1 - i

Solution steps

9 x^{2} + 18 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 \cdot 18}{2 \cdot 9}

Simplify

1 8^{2} - 4 \cdot 9 \cdot 18 : 18 i

x_{1, 2} = \frac{- 18 \pm 18 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 18 + 18 i}{2 \cdot 9}, x_{2} = \frac{- 18 - 18 i}{2 \cdot 9}

x = \frac{- 18 + 18 i}{2 \cdot 9} : - 1 + i

x = \frac{- 18 - 18 i}{2 \cdot 9} : - 1 - i

The solutions to the quadratic equation are:

x = - 1 + i, x = - 1 - i

3 x^{2} - x - 4

\frac{5}{7} (x - 9) = 25

3 = C e^{0}

\frac{x}{5} = \frac{2}{3}

x^{2} = - 9 + 6 x

What are the solutions to the equation 9x^2+18x+18=0 ?
The solutions to the equation 9x^2+18x+18=0 are x=-1+i,x=-1-i
Find the zeros of 9x^2+18x+18=0
The zeros of 9x^2+18x+18=0 are x=-1+i,x=-1-i