What is (a^2+11a+24)/(a^3+27) ?

The solution to (a^2+11a+24)/(a^3+27) is (a+8)/(a^2-3a+9)

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simplify (a^2+11a+24)/(a^3+27)

simplify

\frac{a ^{2} + 11 a + 24}{a ^{3} + 27}

\frac{a + 8}{a ^{2} - 3 a + 9}

Solution steps

\frac{a ^{2} + 11 a + 24}{a ^{3} + 27}

Factor

a^{2} + 11 a + 24 : (a + 3) (a + 8)

= \frac{( a + 3 ) ( a + 8 )}{a ^{3} + 27}

Factor

a^{3} + 27 : (a + 3) (a^{2} - 3 a + 9)

= \frac{( a + 3 ) ( a + 8 )}{( a + 3 ) ( a ^{2} - 3 a + 9 )}

Cancel the common factor:

a + 3

= \frac{a + 8}{a ^{2} - 3 a + 9}

\frac{75 ( 35 )}{85 - 35}

- \frac{19}{2} (\frac{1}{100}) + \frac{19}{2}

\frac{4 x - 1}{5} + \frac{x + 4}{2} = 3

h + 3 \leq 7

\frac{2}{6} + \frac{1}{3}

What is (a^2+11a+24)/(a^3+27) ?
The solution to (a^2+11a+24)/(a^3+27) is (a+8)/(a^2-3a+9)