What are the solutions to the equation x^2=10x-16 ?

The solutions to the equation x^2=10x-16 are x=8,x=2

Find the zeros of x^2=10x-16

The zeros of x^2=10x-16 are x=8,x=2

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x^{2} = 10 x - 16

x = 8, x = 2

Solution steps

x^{2} = 10 x - 16

Move

16

to the left side

x^{2} + 16 = 10 x

Move

10 x

to the left side

x^{2} + 16 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 10 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 16 = 6

x_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 1}

x = \frac{- ( - 10 ) + 6}{2 \cdot 1} : 8

x = \frac{- ( - 10 ) - 6}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 8, x = 2

9 y^{2} + 30 y + 25

x^{2} + x > 12

35 = 1 - \frac{8}{3} - 45 e^{- 1} + x

- \frac{3}{5} \cdot (- 4)

5 m^{2} + 15 m^{3}

What are the solutions to the equation x^2=10x-16 ?
The solutions to the equation x^2=10x-16 are x=8,x=2
Find the zeros of x^2=10x-16
The zeros of x^2=10x-16 are x=8,x=2