What are the solutions to the equation x^2+5x-2=0 ?

The solutions to the equation x^2+5x-2=0 are x=(-5+sqrt(33))/2 ,x=(-5-sqrt(33))/2

Find the zeros of x^2+5x-2=0

The zeros of x^2+5x-2=0 are x=(-5+sqrt(33))/2 ,x=(-5-sqrt(33))/2

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x^{2} + 5 x - 2 = 0

x = \frac{- 5 + 33}{2}, x = \frac{- 5 - 33}{2}

Decimal Notation

x = 0.37228 \dots, x = - 5.37228 \dots

Solution steps

x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 2) = 33

x_{1, 2} = \frac{- 5 \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 33}{2 \cdot 1}, x_{2} = \frac{- 5 - 33}{2 \cdot 1}

x = \frac{- 5 + 33}{2 \cdot 1} : \frac{- 5 + 33}{2}

x = \frac{- 5 - 33}{2 \cdot 1} : \frac{- 5 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 33}{2}, x = \frac{- 5 - 33}{2}

y^{2} - 4 y - 12

\frac{1}{22.1184 \cdot 1 0 ^{6}} \cdot 2^{13}

x y + x^{2} y + x y^{2}

9 x = 10 x + 12

\frac{1}{10.4} - \frac{1}{10.4} \cdot e^{- 10.4 \cdot 0.5}

What are the solutions to the equation x^2+5x-2=0 ?
The solutions to the equation x^2+5x-2=0 are x=(-5+sqrt(33))/2 ,x=(-5-sqrt(33))/2
Find the zeros of x^2+5x-2=0
The zeros of x^2+5x-2=0 are x=(-5+sqrt(33))/2 ,x=(-5-sqrt(33))/2