What are the solutions to the equation x^2+4x+9=0 ?

The solutions to the equation x^2+4x+9=0 are x=-2+sqrt(5)i,x=-2-sqrt(5)i

Find the zeros of x^2+4x+9=0

The zeros of x^2+4x+9=0 are x=-2+sqrt(5)i,x=-2-sqrt(5)i

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x^{2} + 4 x + 9 = 0

x = - 2 + 5 i, x = - 2 - 5 i

Solution steps

x^{2} + 4 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 9 : 25 i

x_{1, 2} = \frac{- 4 \pm 2 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 5 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 5 i}{2 \cdot 1}

x = \frac{- 4 + 2 5 i}{2 \cdot 1} : - 2 + 5 i

x = \frac{- 4 - 2 5 i}{2 \cdot 1} : - 2 - 5 i

The solutions to the quadratic equation are:

x = - 2 + 5 i, x = - 2 - 5 i

- x^{2} - 4 x - 8 \leq - 5

\frac{8}{3} + 2

\frac{4 12}{2 2}

\frac{4}{x - 3} \leq \frac{2}{x - 2}

n^{2} + 11 n + 30 = 0

What are the solutions to the equation x^2+4x+9=0 ?
The solutions to the equation x^2+4x+9=0 are x=-2+sqrt(5)i,x=-2-sqrt(5)i
Find the zeros of x^2+4x+9=0
The zeros of x^2+4x+9=0 are x=-2+sqrt(5)i,x=-2-sqrt(5)i