What are the solutions to the equation -2x^2+8x-8=0 ?

The solutions to the equation -2x^2+8x-8=0 are x=2

Find the zeros of -2x^2+8x-8=0

The zeros of -2x^2+8x-8=0 are x=2

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- 2 x^{2} + 8 x - 8 = 0

x = 2

Solution steps

- 2 x^{2} + 8 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) ( - 8 )}{2 ( - 2 )}

8^{2} - 4 (- 2) (- 8) = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 ( - 2 )}

x = \frac{- 8}{2 ( - 2 )}

\frac{- 8}{2 ( - 2 )} = 2

x = 2

The solution to the quadratic equation is:

x = 2

0.00018 = (\frac{( 1 - x )}{35}) (\frac{( 1.2 - x )}{35})

(- 16)^{0}

5 z + 40 = 62

∣ 3 x - 9 ∣ + 6 \leq 4

x^{2} - 6 x - 16

What are the solutions to the equation -2x^2+8x-8=0 ?
The solutions to the equation -2x^2+8x-8=0 are x=2
Find the zeros of -2x^2+8x-8=0
The zeros of -2x^2+8x-8=0 are x=2