What are the solutions to the equation 3x^2+9x-2x-6=0 ?

The solutions to the equation 3x^2+9x-2x-6=0 are x= 2/3 ,x=-3

Find the zeros of 3x^2+9x-2x-6=0

The zeros of 3x^2+9x-2x-6=0 are x= 2/3 ,x=-3

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3 x^{2} + 9 x - 2 x - 6 = 0

x = \frac{2}{3}, x = - 3

Solution steps

3 x^{2} + 9 x - 2 x - 6 = 0

Refine

3 x^{2} + 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 6) = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 \cdot 3}, x_{2} = \frac{- 7 - 11}{2 \cdot 3}

x = \frac{- 7 + 11}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 7 - 11}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 3

\frac{2 π}{\frac{4 π}{3}}

(- 128)^{\frac{1}{7}}

288 x^{2} y^{5}

x^{2} + 9 = 0

- 8 = \frac{6}{5} u

What are the solutions to the equation 3x^2+9x-2x-6=0 ?
The solutions to the equation 3x^2+9x-2x-6=0 are x= 2/3 ,x=-3
Find the zeros of 3x^2+9x-2x-6=0
The zeros of 3x^2+9x-2x-6=0 are x= 2/3 ,x=-3